CU06997 Lecture 13 ; Exercises
Author: hzhenk
CU06997 Lecture 12 ; Exercises
Link to computation Ditch with a length of 700 m. Bed-slope is 1:3000, Downstream bed level is +0, m N.A.P. Downstream a weir; width 5 m, m= 1,7, level crest 0,7 m N.A.P, free flow. Cross section; bed width 2 …
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CU06997 Lecture 11 ; Exercises
Link to lecture 11 Link naar les 11 Link to computation Exercise
CU06997 Lecture 10 ; Exercises
Link to lecture 10 Link naar les 10 Link to computation Exercise
CU06997 Lecture 9 ; Exercises
Link to lecture 9 Link naar les 9 Link to computation
CU06997 Lecture 8 ; Exercises
Link to lecture 8 Link to les 8 Link to computation At the end of the lecture, there is already a first introduction Additional information: – equivalent roughness k-concrete = 1,5 mm, k-PVC = 1 mm – width weir = …
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CU06997 Lecture 7 ; Exercises
Link to lecture 7 Link naar les 7 Link to computation All questions have to do with the following culvert Length culvert is 50 m, width culvert = 2 m , height culvert = 2 m, friction coefficient λ=0,022 and …
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CU06997 Lecture 6 ; Exercises
Link to computation Link to lecture 6 Link naar les 6 Exercise 1 Exercise 2 Exercise 3 Exercise 4
CU06997 Exercise lecture 5 ; computation
Link to exercise lecture 5 Exercise 1 plus answer Water-depth (D) = 1,5 m at P1 and P2 Discharge Q = 21 m3/s Bed width ditch (W) = 4 m Slope ditch (S) = 1:3Questions: Calculate the Hydraulic Radius for …
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Newton Force
F = m · g [N] m = weight [Kg] g = earths gravity [m/s2]