CU06997 Lecture 10 ; Exercises
Link to lecture 10 Link naar les 10 Link to computation Exercise
Category: Course Fluid Dynamics
CU06997 Lecture 9 ; Exercises
Link to lecture 9 Link naar les 9 Link to computation
CU06997 Lecture 8 ; Exercises
Link to lecture 8 Link to les 8 Link to computation At the end of the lecture, there is already a first introduction Additional information: – equivalent roughness k-concrete = 1,5 mm, k-PVC = 1 mm – width weir = …
CU06997 Lecture 8 ; Exercises Read more »
CU06997 Lecture 7 ; Exercises
Link to lecture 7 Link naar les 7 Link to computation All questions have to do with the following culvert Length culvert is 50 m, width culvert = 2 m , height culvert = 2 m, friction coefficient λ=0,022 and …
CU06997 Lecture 7 ; Exercises Read more »
CU06997 Lecture 6 ; Exercises
Link to computation Link to lecture 6 Link naar les 6 Exercise 1 Exercise 2 Exercise 3 Exercise 4
CU06997 Exercise lecture 5 ; computation
Link to exercise lecture 5 Exercise 1 plus answer Water-depth (D) = 1,5 m at P1 and P2 Discharge Q = 21 m3/s Bed width ditch (W) = 4 m Slope ditch (S) = 1:3Questions: Calculate the Hydraulic Radius for …
CU06997 Exercise lecture 5 ; computation Read more »
Newton Force
F = m · g [N] m = weight [Kg] g = earths gravity [m/s2]
CU06997 Lecture 5 ; Exercises
Link to computation / answer Link to lecture 5 Link naar les 5 Exercise 1 Water-depth (D) = 1,5 m at P1 and P2 Discharge Q = 21 m3/s Bed width ditch (W) = 4 m Slope ditch (S) = …
CU06997 Lecture 5 ; Exercises Read more »
CU06997 Exercise lecture 4 ; computation
Link to exercise Slides Cu06997 lecture 4_answer from Henk Massink Exercise 1 Exercise 2 Exercise 3
CU06997 Lecture 4 ; Exercises
Link to computation / answer Link to lecture 4 Link naar les 4 Exercise 1 For the frictionless syphon in Figure 2.4 (So there is no energy loss), determine the discharge and the pressure heads at A and B, given …
CU06997 Lecture 4 ; Exercises Read more »